6x^2-40x-200=0

Solution for 6x^2-40x-200=0 equation:

6x^2-40x-200=0

a = 6; b = -40; c = -200;
Δ = b2-4ac
Δ = -402-4·6·(-200)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6400}=80$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-80}{2*6}=\frac{-40}{12}
=-3+1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+80}{2*6}=\frac{120}{12}
=10
$